Mine ventilation case calculation
 
     Let consider the following ventilation network in a mine. The network is made of five branches and four nodes.     The airflow which gets in the mine is 47 m 3 /s.   The Hardy Cross method will be used to compute the natural distribution of air flow in the different parts of the mine.         Branch      R      Q          2      0.4      30          3      0.6      17          4      0.1      3          5      0.5      27          6      0.7      20        R is the airway resistance in kg/m 7   1st case   We will start by considering an arbitrary distribution which respects the nodes law (the sum of incoming flows is equal to the sum of outgoing flows in a node)   If the distribution is real, the sum of head losses along any loop is zero.   The number of independent loops is given by b-n+1 where b is the number of branches and n the number of nodes.   In the present case the number of loops is 5-4+1=2   The chosen loops are 243 and  564. We walk along the loops clockwise. If t...
