Mine ventilation case calculation
Let consider the following ventilation network in a mine. The network is made of five branches and four nodes. The airflow which gets in the mine is 47 m 3 /s. The Hardy Cross method will be used to compute the natural distribution of air flow in the different parts of the mine. Branch R Q 2 0.4 30 3 0.6 17 4 0.1 3 5 0.5 27 6 0.7 20 R is the airway resistance in kg/m 7 1st case We will start by considering an arbitrary distribution which respects the nodes law (the sum of incoming flows is equal to the sum of outgoing flows in a node) If the distribution is real, the sum of head losses along any loop is zero. The number of independent loops is given by b-n+1 where b is the number of branches and n the number of nodes. In the present case the number of loops is 5-4+1=2 The chosen loops are 243 and 564. We walk along the loops clockwise. If the f